mute-gold•17mo ago

Array Variables?

ChatGPT 3.5 tells me to use array variables in VF to create a bunch (100) of variables, but I think it's lying because I don't see an option to set a variable type and couldn't find in documentation. Is this fake news, or is this something I maybe need to do completely in JS? Thanks for any insight!

3 Replies

Tico | Voiceflow Assistant•17mo ago

In Voiceflow, you can indeed use array variables, but the process might not be as straightforward as in traditional programming languages. Voiceflow doesn't explicitly have an option to set a variable type like 'array', but you can still create and manipulate arrays using the built-in functionality. To create an array, you can use the 'Set' block in Voiceflow. For instance, if you want to create an array of numbers, you can use the 'Set' block and assign a variable (let's call it 'numbers') a value like this: [1, 2, 3, 4, 5]. This will create an array of numbers. To manipulate or access elements in the array, you can use the 'Code' block. For example, to access the first element of the 'numbers' array, you can use 'numbers[0]'. To add an element to the array, you can use the 'push' method like this: 'numbers.push(6)'. However, please note that while you can create and manipulate arrays in Voiceflow, the platform is primarily designed for designing conversational experiences and not for complex programming tasks. If you need to perform complex operations on arrays or other data structures, you might need to use a more traditional programming language and integrate it with Voiceflow using the API block. I hope this helps! If you have any more questions, feel free to ask.

W. Williams (SFT)•17mo ago

You can also use a Javascript step. So if you have a VF var call myVariable you would do this:

myVariable = {
  otherVar1: 'text',
  otherVar2: 0,
  otherVar3: [ 'this', 'is', 'an', 'array' ],
}

myVariable = {
  otherVar1: 'text',
  otherVar2: 0,
  otherVar3: [ 'this', 'is', 'an', 'array' ],
}

NOTE: You cannot output this data within VF because it is an object. You will need to set another var to a one of the values like this:

outputVar = myVariable.otherVar1

outputVar = myVariable.otherVar1

mute-goldOP•17mo ago

Thank you! I'll play around with this.

Array Variables?

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